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Proof step 4 from proof short-2bytes-03 (previous step)

by ' ≠ [], 0 < bytes2int(by ') * 256 + band(b2i(by0), 255), 32768 < bytes2int(by ') * 256 + band(b2i(by0), 255) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < band(b2i(by0), 255) + 256 * b2i(by), 32768 < band(b2i(by0), 255) + 256 * b2i(by) ⊦

Rule argument

Additional information

Used simplifier rules: bytes2int-one: ⊦ bytes2int(by ') = b2i(by);%i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i + j = j + i;% ⊦ i * j = j * i;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ by ' ≠ [];