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Proof step 3 from proof short-2bytes (previous step)

¬(~32768 ≤ bytes2int(by ' + by0 ') ∧ bytes2int(by ' + by0 ') ≤ 32767) ⊦ s2i(i2s(bytes2int(by ' + by0 '))) = bytes2int(by ' + by0 ')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ s2i(i2s(bytes2int(by ' + by0 '))) = bytes2int(by ' + by0 '), ¬ bytes2int(by ' + by0 ') < ~32768 ∧ ¬ 32767 < bytes2int(by ' + by0 ')

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;