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Proof step 8 from proof short-2bytes (previous step)

⊦ ¬ band(b2i(by0), 255) + 256 * b2i(by) < ~32768, s2i(i2s(band(b2i(by0), 255) + 256 * b2i(by))) = band(b2i(by0), 255) + 256 * b2i(by)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
band(b2i(by0), 255) + 256 * b2i(by) < ~32768, band(b2i(by0), 255) + 256 * b2i(by) < 0 ⊦ s2i(i2s(band(b2i(by0), 255) + 256 * b2i(by))) = band(b2i(by0), 255) + 256 * b2i(by)

Rule argument

Additional information

Used simplifier rules: ⊦ i + j + i0 = (i + j) + i0;% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)% ⊦ i + j = j + i;% ⊦ i * j = j * i;