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Proof step 7 from proof sqrt-isSquare (previous step)

isSquare(dec0 * dec0) ⊦ mkDecimal(sqrt((dec0 * dec0).int), (dec0 * dec0).scale / 2) * mkDecimal(sqrt((dec0 * dec0).int), (dec0 * dec0).scale / 2) = dec0 * dec0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
⊦ mkDecimal(sqrt((dec0 * dec0).int), (dec0 * dec0).scale / 2) * mkDecimal(sqrt((dec0 * dec0).int), (dec0 * dec0).scale / 2) = dec0 * dec0

Rule argument

Additional information

Used simplifier rules: isSquare-square: ⊦ isSquare(dec * dec);%mult-c: ⊦ dec_i * dec_j = dec_j * dec_i; from specification decimal-simple-ops%mult-a: ⊦ dec0 * dec1 * dec2 = (dec0 * dec1) * dec2; from specification decimal-simple-ops