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Proof step 12 from proof test-div-01 (previous step)

¬(3 % 10 = 0 ∧ 0 ≠ 0 ∧ 3 ≠ 0) ⊦ mkDecimal(10 ^ (abs(0) + 4) / mkDecimal(3, 0).int / 10 ^ maxScale(mkDecimal(3, 0).int), mkDecimal(1, 0).scale + 4 + maxScale(mkDecimal(3, 0).int)) = mkDecimal(3333, 4), mkDecimal(3, 0) | mkDecimal(1, 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
⊦ mkDecimal(10000 / mkDecimal(3, 0).int / 10 ^ maxScale(mkDecimal(3, 0).int), mkDecimal(1, 0).scale + 4 + maxScale(mkDecimal(3, 0).int)) = mkDecimal(3333, 4), mkDecimal(3, 0) | mkDecimal(1, 0)

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2