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Proof step 3 from proof test-div-01 (previous step)

¬ ¬ mkDecimal(3, 0) | mkDecimal(1, 0) ⊦ div(mkDecimal(1, 0), mkDecimal(3, 0), 4) = mkDecimal(3333, 4)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information