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Proof step 19 from proof test-div-02 (previous step)

¬(2 % 10 = 0 ∧ 0 ≠ 0 ∧ 2 ≠ 0), div(mkDecimal(5, 0), mkDecimal(2, 0), 0) * mkDecimal(2, 0) = mkDecimal(5, 0) ⊦ mkDecimal(25 * 2, mkDecimal(25, 1).scale + mkDecimal(2, 0).scale) = mkDecimal(5, 0), div(mkDecimal(5, 0), mkDecimal(2, 0), 0) = mkDecimal(25, 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
div(mkDecimal(5, 0), mkDecimal(2, 0), 0) * mkDecimal(2, 0) = mkDecimal(5, 0) ⊦ div(mkDecimal(5, 0), mkDecimal(2, 0), 0) = mkDecimal(25, 1), mkDecimal(50, mkDecimal(25, 1).scale + mkDecimal(2, 0).scale) = mkDecimal(5, 0)

Rule argument

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult