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Proof step 22 from proof test-div-02 (previous step)

¬(25 % 10 = 0 ∧ 1 ≠ 0 ∧ 25 ≠ 0), div(mkDecimal(5, 0), mkDecimal(2, 0), 0) * mkDecimal(2, 0) = mkDecimal(5, 0) ⊦ div(mkDecimal(5, 0), mkDecimal(2, 0), 0) = mkDecimal(25, 1), mkDecimal(50, abs(1) + mkDecimal(2, 0).scale) = mkDecimal(5, 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
div(mkDecimal(5, 0), mkDecimal(2, 0), 0) * mkDecimal(2, 0) = mkDecimal(5, 0) ⊦ div(mkDecimal(5, 0), mkDecimal(2, 0), 0) = mkDecimal(25, 1), mkDecimal(50, 1 + mkDecimal(2, 0).scale) = mkDecimal(5, 0)

Proof step 22 from proof test-div-02 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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