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Proof step 25 from proof test-div-02 (previous step)

¬(2 % 10 = 0 ∧ 0 ≠ 0 ∧ 2 ≠ 0), div(mkDecimal(5, 0), mkDecimal(2, 0), 0) * mkDecimal(2, 0) = mkDecimal(5, 0) ⊦ div(mkDecimal(5, 0), mkDecimal(2, 0), 0) = mkDecimal(25, 1), mkDecimal(50, 1 + abs(0)) = mkDecimal(5, 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2