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Proof step 28 from proof test-div-03 (previous step)

1000 % 10 = 0 ∧ 3 ≠ 0, div(mkDecimal(1, 0), mkDecimal(1000, 0), 0) * mkDecimal(1000, 0) = mkDecimal(1, 0) ⊦ div(mkDecimal(1, 0), mkDecimal(1000, 0), 0) = mkDecimal(1, 3), mkDecimal(1000 / 10, abs(3) - 1) = mkDecimal(1, 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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