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Proof step 3 from proof test-div-03 (previous step)

⊦ div(mkDecimal(1, 0), mkDecimal(1000, 0), 0) = mkDecimal(1, 3)

User applied rule insert lemma

And obtained the following new goals

Proof step 4:
⊦ dec_j | dec_i → div(dec_i, dec_j, i) * dec_j = dec_i
Proof step 5:
mkDecimal(1000, 0) | mkDecimal(1, 0) → div(mkDecimal(1, 0), mkDecimal(1000, 0), 0) * mkDecimal(1000, 0) = mkDecimal(1, 0) ⊦ div(mkDecimal(1, 0), mkDecimal(1000, 0), 0) = mkDecimal(1, 3)

Rule argument

spec: inst: name: div-exact-def seq: ⊦ dec_j | dec_i → div(dec_i, dec_j, i) * dec_j = dec_i subst: [dec_j, dec_i, i] → [mkDecimal(1000, 0), mkDecimal(1, 0), 0] flags: current, []

Additional information

Used terms: mkDecimal(1000, 0), mkDecimal(1, 0), 0