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Proof step 22 from proof test-div-04 (previous step)

¬(123123 % 10 = 0 ∧ 0 ≠ 0 ∧ 123123 ≠ 0), div(mkDecimal(5540535, 4), mkDecimal(45, 4), 0) * mkDecimal(45, 4) = mkDecimal(5540535, 4) ⊦ div(mkDecimal(5540535, 4), mkDecimal(45, 4), 0) = mkDecimal(123123, 0), mkDecimal(5540535, abs(0) + mkDecimal(45, 4).scale) = mkDecimal(5540535, 4)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-zero: ⊦ i + 0 = i; from specification int-basic2