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Proof step 23 from proof test-divides-01 (previous step)

¬(1 % 10 = 0 ∧ 0 ≠ 0 ∧ 1 ≠ 0), mkDecimal(3 * i, abs(i0)).scale = abs(0), mkDecimal(3 * i, abs(i0)).int = 1, ∀ i1, i0. i→n(i1) < i→n(i) → mkDecimal(3 * i1, abs(i0)) = mkDecimal(1, 0) → false ⊦ i0 = 0, (3 * i) % 10 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
mkDecimal(3 * i, abs(i0)).int = 1, mkDecimal(3 * i, abs(i0)).scale = 0, ∀ i1, i0. i→n(i1) < i→n(i) → mkDecimal(3 * i1, abs(i0)) = mkDecimal(1, 0) → false ⊦ i0 = 0, (3 * i) % 10 = 0

Proof step 23 from proof test-divides-01 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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