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Proof step 27 from proof test-divides-01 (previous step)

(3 * i) % 10 = 0, mkDecimal((3 * i) / 10, abs(i0) - 1) = mkDecimal(1, 0), ∀ i1, i0. i→n(i1) < i→n(i) → mkDecimal(3 * i1, abs(i0)) = mkDecimal(1, 0) → false ⊦ i0 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 28:
(3 * i) / 10 = 3 * i / 10, (3 * i) % 10 = 0, mkDecimal((3 * i) / 10, abs(i0) - 1) = mkDecimal(1, 0), ∀ i1, i0. i→n(i1) < i→n(i) → mkDecimal(3 * i1, abs(i0)) = mkDecimal(1, 0) → false ⊦ i0 = 0
Proof step 30:
(3 * i) % 10 = 0, mkDecimal((3 * i) / 10, abs(i0) - 1) = mkDecimal(1, 0), ∀ i1, i0. i→n(i1) < i→n(i) → mkDecimal(3 * i1, abs(i0)) = mkDecimal(1, 0) → false ⊦ (3 * i) / 10 = 3 * i / 10, i0 = 0

Rule argument

fma: (3 * i) / 10 = 3 * i / 10

Additional information

Used formulas: (3 * i) / 10 = 3 * i / 10