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Proof step 33 from proof test-divides-01 (previous step)

(3 * i) % 10 = 0, mkDecimal((3 * i) / 10, abs(i0) - 1) = mkDecimal(1, 0), i % 10 = 0, ∀ i1, i0. i→n(i1) < i→n(i) → mkDecimal(3 * i1, abs(i0)) = mkDecimal(1, 0) → false ⊦ (3 * i) / 10 = 3 * i / 10, i0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 34:
j ≠ 0, j0 % j = 0 ⊦ (i * (* j0)) / (* j) = i * j0 / j

Rule argument

spec: int-div inst: name: div-mult-num seq: j ≠ 0, j0 % j = 0 ⊦ (i * (* j0)) / (* j) = i * j0 / j subst: [j, j0, i] → [10, i, 3] flags: rewrite

Additional information

Used terms: 10, i, 3