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Proof step 15 from proof test-sqrt-02 (previous step)

141 ^2 ≤ 20000 ∧ 20000 < (141 + 1)^2 ∧ 0 ≤ 141 → sqrt(20000) = 141 ⊦ sqrt(20000) = 141

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
⊦ sqrt(20000) = 141, 141 ^2 ≤ 20000 ∧ 20000 < 142 ^2

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2