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Proof step 6 from proof test-sqrt-05 (previous step)

¬(29 % 10 = 0 ∧ 5 ≠ 0 ∧ 29 ≠ 0) ⊦ sqrt(mkDecimal(29, 5), 3) = mkDecimal(17029, 6), odd(abs(5))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information