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Proof step 14 from proof abs-any-def (
previous step
)
∀ i0, j. i→n(i0) < i→n(i) → true → abs(mkDecimal(i0, j)) = mkDecimal(abs(i0), j) ⊦ mkDecimal(abs(i), abs(j)) = mkDecimal(abs(i), j), i = 0, i % 10 = 0, j = 0
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 15
:
⊦ mkDecimal(i, j) = mkDecimal(i, abs(j))
Rule argument
spec: decimal inst: name: mkDecimal-scale-not-neg seq: ⊦ mkDecimal(i, j) = mkDecimal(i, abs(j)) subst: [j, i] → [j, abs(i)] flags: rewrite
Additional information
Used terms: j, abs(i)