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Proof step 6 from proof abs-any-def (previous step)

∀ i0, j. i→n(i0) < i→n(i) → true → abs(mkDecimal(i0, j)) = mkDecimal(abs(i0), j) ⊦ abs(mkDecimal(i, j)) = mkDecimal(abs(i), j), i % 10 = 0 ∧ j ≠ 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ abs(dec_i) = mkDecimal(abs(dec_i.int), dec_i.scale)
Proof step 8:
∀ i0, j. i→n(i0) < i→n(i) → true → abs(mkDecimal(i0, j)) = mkDecimal(abs(i0), j) ⊦ mkDecimal(abs(mkDecimal(i, j).int), mkDecimal(i, j).scale) = mkDecimal(abs(i), j), i % 10 = 0 ∧ j ≠ 0

Rule argument

spec: inst: name: abs-def seq: ⊦ abs(dec_i) = mkDecimal(abs(dec_i.int), dec_i.scale) subst: [dec_i] → [mkDecimal(i, j)] flags: rewrite, current

Additional information

Used terms: mkDecimal(i, j)