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Proof step 3 from proof abs-pos (previous step)

dec = mkDecimal(i, i0), mkDecimal(0, 0) ≤ dec ⊦ abs(dec) = dec

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 ≤ i ⊦ abs(mkDecimal(i, i0)) = mkDecimal(i, i0)

Rule argument

Additional information

Used simplifier rules: le-zero: ⊦ mkDecimal(0, 0) ≤ mkDecimal(i, j) ↔ 0 ≤ i;%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs