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Proof step 18 from proof add-scale-neq (
previous step
)
⊦ 0 ≤ j ∧ 0 ≤ j0 → i * 10 ^ j + i0 * 10 ^ j0 = (i * 10 ^ (j - min(j, j0)) + i0 * 10 ^ (j0 - min(j, j0))) * 10 ^ min(j, j0)
A spec-lemma