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Proof step 87 from proof add-scale-neq (previous step)

0 ≤ min(dec_j.scale, dec_i.scale) ∧ dec_i.int * 10 ^ (dec_j.scale - min(dec_j.scale, dec_i.scale)) + dec_j.int * 10 ^ (dec_i.scale - min(dec_j.scale, dec_i.scale)) ≠ 0, dec_i.scale + dec_j.scale < maxScale(dec_i.int * 10 ^ (dec_j.scale - min(dec_j.scale, dec_i.scale)) + dec_j.int * 10 ^ (dec_i.scale - min(dec_j.scale, dec_i.scale))) + min(dec_j.scale, dec_i.scale), 0 ≤ dec_j.scale, 0 ≤ dec_i.scale ⊦ dec_i.scale = dec_j.scale, 0 = max(dec_i.scale, dec_j.scale)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 88:
dec_i.scale + dec_j.scale < maxScale(dec_i.int * 10 ^ (dec_j.scale - min(dec_j.scale, dec_i.scale)) + dec_j.int * 10 ^ (dec_i.scale - min(dec_j.scale, dec_i.scale))) + min(dec_j.scale, dec_i.scale), 0 ≤ dec_j.scale, 0 ≤ dec_i.scale, 0 ≤ min(dec_j.scale, dec_i.scale) ⊦ dec_i.scale = dec_j.scale, 0 = max(dec_i.scale, dec_j.scale), dec_i.int * 10 ^ (dec_j.scale - min(dec_j.scale, dec_i.scale)) + dec_j.int * 10 ^ (dec_i.scale - min(dec_j.scale, dec_i.scale)) = 0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs