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Proof step 4 from proof le-trans (
previous step
)
dec0 ≤ dec1, dec ≤ dec0 ⊦ dec < dec1 ∨ dec = dec1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
dec ≤ dec0, dec0 ≤ dec1 ⊦ dec = dec1, dec < dec1
Rule argument
Additional information