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Proof step 7 from proof le-trans (previous step)

dec ≤ dec0, dec0 < dec1 ∨ dec0 = dec1 ⊦ dec = dec1, dec < dec1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
dec ≤ dec1 ⊦ dec = dec1, dec < dec1

Rule argument

Additional information

Used simplifier rules: le-ls-trans: ⊦ dec ≤ dec0 ∧ dec0 < dec1 → dec < dec1;%less-irref: ⊦ ¬ dec < dec;