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Proof step 1 from proof square-abs (conclusion)

⊦ abs(dec * dec) = dec * dec

User applied rule constructor cut

And obtained the following new goals

Proof step 2:
dec = mkDecimal(i, i0) ⊦ abs(dec * dec) = dec * dec

Rule argument

var: dec

Additional information

Used simplifier rules: decimal generated by mkDecimal;;