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Proof step 7 from proof square-isSquare (previous step)

true, ∀ i1, i0. i→n(i1) < i→n(i) → true → isSquare(mkDecimal(i1 * i1, 2 * abs(i0)).int) ⊦ isSquare(mkDecimal(i * i, 2 * abs(i0)).int)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information