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Proof step 10 from proof square-ls (previous step)

⊦ mkDecimal(i * i, 2 * abs(i0)) < mkDecimal(i1 * i1, abs(i2) + abs(i2)) ↔ abs(mkDecimal(i, i0)) < abs(mkDecimal(i1, i2))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ mkDecimal(i * i, 2 * abs(i0)) < mkDecimal(i1 * i1, 2 * abs(i2)) ↔ abs(mkDecimal(i, i0)) < abs(mkDecimal(i1, i2))

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-mult-two: ⊦ i + i = 2 * i; from specification int-mult