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Proof step 28 from proof square-ls (previous step)

⊦ abs(i) * 10 ^ abs(i2) < abs(i1) * 10 ^ abs(i0) ↔ mkDecimal(abs(i), i0) < abs(mkDecimal(i1, i2))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 29:
⊦ abs(mkDecimal(i, j)) = mkDecimal(abs(i), j)
Proof step 30:
⊦ abs(i) * 10 ^ abs(i2) < abs(i1) * 10 ^ abs(i0) ↔ mkDecimal(abs(i), i0) < mkDecimal(abs(i1), i2)

Rule argument

spec: inst: name: abs-any-def seq: ⊦ abs(mkDecimal(i, j)) = mkDecimal(abs(i), j) subst: [j, i] → [i2, i1] flags: rewrite, current

Additional information

Used terms: i2, i1