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Proof step 1 from proof square-pos-01 (conclusion)

⊦ mkDecimal(0, 0) < dec * dec ↔ dec ≠ mkDecimal(0, 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
dec * dec ≤ mkDecimal(0, 0) ⊦ dec = mkDecimal(0, 0)

Rule argument

Additional information

Used simplifier rules: mult-zero-01: ⊦ mkDecimal(0, 0) * dec = mkDecimal(0, 0);%mult-a: ⊦ dec0 * dec1 * dec2 = (dec0 * dec1) * dec2;%mult-c: ⊦ dec_i * dec_j = dec_j * dec_i;%ls-zero: ⊦ mkDecimal(0, 0) < mkDecimal(i, j) ↔ 0 < i;%ls-not: ⊦ ¬ dec < dec0 ↔ dec0 ≤ dec;