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Proof step 3 from proof square-pos-01 (previous step)

dec = mkDecimal(i, i0), dec * dec ≤ mkDecimal(0, 0) ⊦ dec = mkDecimal(0, 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: eq-zero: ⊦ mkDecimal(i, j) = mkDecimal(0, j0) ↔ i = 0; from specification decimal