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Proof step 5 from proof square-sqrt-02 (previous step)

dec.scale % 2 = 0, j * j = dec.int ⊦ mkDecimal(sqrt(j * j), dec.scale / 2) * mkDecimal(sqrt(j * j), dec.scale / 2) = dec

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ sqrt(i * i) = abs(i)
Proof step 7:
dec.scale % 2 = 0, j * j = dec.int ⊦ mkDecimal(abs(j), dec.scale / 2) * mkDecimal(abs(j), dec.scale / 2) = dec

Rule argument

spec: int-square inst: name: inverse-ii seq: ⊦ sqrt(i * i) = abs(i) subst: [i] → [j] flags: rewrite

Additional information

Used terms: j