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Proof step 20 from proof sub-add (previous step)

⊦ i = 0, 10 ^ abs(i2) * 10 ^ abs(i2) = 10 ^ (2 * abs(i2))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ 0 ≤ j → i ^ (2 * j) = i ^ j * i ^ j

Rule argument

spec: int-pot inst: name: pot-square-06 seq: ⊦ 0 ≤ j → i ^ (2 * j) = i ^ j * i ^ j subst: [j, i] → [abs(i2), 10] flags: rewrite

Additional information

Used simplifier rules: abs-03: ⊦ 0 ≤ abs(i); from specification int-abs Used terms: abs(i2), 10