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Proof step 3 from proof sub-same (previous step)

⊦ mkDecimal(i * 10 ^ abs(j) - i0 * 10 ^ abs(j), abs(j) + abs(j)) = mkDecimal(i - i0, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ mkDecimal(i * 10 ^ abs(j) - i0 * 10 ^ abs(j), 2 * abs(j)) = mkDecimal(i - i0, j)

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-mult-two: ⊦ i + i = 2 * i; from specification int-mult