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Proof step 15 from proof eq-same (previous step)

¬(i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0), i = mkDecimal(i0, j).int, abs(j) = mkDecimal(i0, j).scale, ∀ i1, i2, j. i→n(i1) + i→n(i2) < i→n(i) + i→n(i0) → mkDecimal(i1, j).scale = mkDecimal(i2, j).scale ∧ mkDecimal(i1, j).int = mkDecimal(i2, j).int → i1 = i2 ⊦ i = i0, i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0, i % 10 = 0 ∧ j ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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