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Proof step 24 from proof eq-same (previous step)

i0 % 10 = 0 ∧ j ≠ 0 ∧ i0 ≠ 0, abs(j) = mkDecimal(i0, j).scale, ∀ i1, i2, j0. i→n(i1) + i→n(i2) < i→n(mkDecimal(i0 / 10, abs(j) - 1).int) + i→n(i0) → mkDecimal(i1, j0).scale = mkDecimal(i2, j0).scale ∧ mkDecimal(i1, j0).int = mkDecimal(i2, j0).int → i1 = i2 ⊦ mkDecimal(i0 / 10, abs(j) - 1).int = i0, mkDecimal(i0 / 10, abs(j) - 1).int % 10 = 0 ∧ j ≠ 0, mkDecimal(i0 / 10, abs(j) - 1).int % 10 = 0 ∧ j ≠ 0 ∧ mkDecimal(i0 / 10, abs(j) - 1).int ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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