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Proof step 37 from proof eq-same (previous step)

¬(mkDecimal(i / 10, abs(j) - 1).int % 10 = 0 ∧ j ≠ 0 ∧ mkDecimal(i / 10, abs(j) - 1).int ≠ 0), mkDecimal(i / 10, abs(j) - 1).scale = abs(j), i % 10 = 0, ∀ i1, i2, j0. i→n(i1) + i→n(i2) < i→n(i) + i→n(mkDecimal(i / 10, abs(j) - 1).int) → mkDecimal(i1, j0).scale = mkDecimal(i2, j0).scale ∧ mkDecimal(i1, j0).int = mkDecimal(i2, j0).int → i1 = i2 ⊦ j = 0, mkDecimal(i / 10, abs(j) - 1).int % 10 = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: scale-neq-01: ⊦ j ≠ 0 → mkDecimal(i, abs(j) - 1).scale ≠ abs(j);