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Proof step 52 from proof equality-any (previous step)

¬(10 ^ (abs(j0) - abs(j)) % 10 = 0 ∧ 10 ≠ 0), abs(j) < abs(j0), ∀ i1, i2, j2, j1. i→n(i1) + i→n(i2) < i→n(i) + i→n(i * 10 ^ (abs(j0) - abs(j))) → true → (mkDecimal(i1, j2) = mkDecimal(i2, j1) ↔ i1 * 10 ^ abs(j1) = i2 * 10 ^ abs(j2)) ⊦ i % 10 = 0, (i * 10 ^ (abs(j0) - abs(j))) % 10 = 0, i = 0, abs(j) = abs(j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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