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Proof step 58 from proof equality-any (previous step)

¬(10 ^ (abs(j) - abs(j0)) % 10 = 0 ∧ 10 ≠ 0), abs(j0) < abs(j), ∀ i1, i2, j1, j2. i→n(i1) + i→n(i2) < i→n(i0 * 10 ^ (abs(j) - abs(j0))) + i→n(i0) → true → (mkDecimal(i1, j1) = mkDecimal(i2, j2) ↔ i1 * 10 ^ abs(j2) = i2 * 10 ^ abs(j1)) ⊦ (i0 * 10 ^ (abs(j) - abs(j0))) % 10 = 0, i0 % 10 = 0, i0 = 0, abs(j) = abs(j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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