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Proof step 8 from proof getint-neg-02 (previous step)

i % 10 = 0 ∧ j ≠ 0, ∀ i0, j. i→n(i0) < i→n(i) → true → (mkDecimal(i0, j).int < 0 ↔ i0 < 0) ⊦ mkDecimal(i / 10, abs(j) - 1).int < 0 ↔ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information