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Proof step 11 from proof getint-neg (previous step)

i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0, ∀ i0, j. i→n(i0) < i→n(i) → true → ~ mkDecimal(i0, j).int = mkDecimal(~ i0, j).int ⊦ mkDecimal(i / 10, abs(j) - 1).int + mkDecimal(~ i, j).int = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
i % 10 = 0, ∀ i0, j. i→n(i0) < i→n(i) → true → ~ mkDecimal(i0, j).int = mkDecimal(~ i0, j).int ⊦ j = 0, i = 0, mkDecimal(i / 10, abs(j) - 1).int + mkDecimal(~ i, j).int = 0

Proof step 11 from proof getint-neg (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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