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Proof step 5 from proof getint-neg (previous step)

¬(i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0), ∀ i0, j. i→n(i0) < i→n(i) → true → ~ mkDecimal(i0, j).int = mkDecimal(~ i0, j).int ⊦ mkDecimal(i, j).int + mkDecimal(~ i, j).int = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
∀ i0, j. i→n(i0) < i→n(i) → true → ~ mkDecimal(i0, j).int = mkDecimal(~ i0, j).int ⊦ mkDecimal(i, j).int + mkDecimal(~ i, j).int = 0, i = 0, j ≠ 0 ∧ i % 10 = 0

Rule argument

Additional information

Used simplifier rules: intvalue-zero: ⊦ mkDecimal(0, j).int = 0;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2