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Proof step 5 from proof getint-pos (previous step)

¬(i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0), ∀ i0, j. i→n(i0) < i→n(i) → true → (0 < mkDecimal(i0, j).int ↔ 0 < i0) ⊦ 0 < mkDecimal(i, j).int ↔ 0 < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
∀ i0, j. i→n(i0) < i→n(i) → true → (0 < mkDecimal(i0, j).int ↔ 0 < i0) ⊦ 0 < mkDecimal(i, j).int ↔ 0 < i, i = 0, j ≠ 0 ∧ i % 10 = 0

Rule argument

Additional information

Used simplifier rules: intvalue-zero: ⊦ mkDecimal(0, j).int = 0;