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Proof step 8 from proof getint-pos (previous step)

i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0, ∀ i0, j. i→n(i0) < i→n(i) → true → (0 < mkDecimal(i0, j).int ↔ 0 < i0) ⊦ 0 < mkDecimal(i / 10, abs(j) - 1).int ↔ 0 < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information