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Proof step 2 from proof maxScale-not-negt (previous step)

true, ∀ i0. i→n(i0) < i→n(i) → true → ¬ maxScale(i0) < 0 ⊦ ¬ maxScale(i) < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
maxScale(i) < 0, ∀ i0. i→n(i0) < i→n(i) → true → ¬ maxScale(i0) < 0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs