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Proof step 4 from proof maxScale-pot10-01 (previous step)

0 ≤ j, ∀ j0, i. i→n(j0) < i→n(j) → 0 ≤ j0 → maxScale(i * 10 ^ j0) = j0 ∨ i % 10 = 0 ⊦ i % 10 = 0, maxScale(i * 10 ^ j) = j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ 0 < i → j ^ i = j ^ i -1 * j
Proof step 6:
¬ 0 < j, 0 ≤ j, ∀ j0, i. i→n(j0) < i→n(j) → 0 ≤ j0 → maxScale(i * 10 ^ j0) = j0 ∨ i % 10 = 0 ⊦ i % 10 = 0, maxScale(i * 10 ^ j) = j
Proof step 9:
0 < j, 0 ≤ j, ∀ j0, i. i→n(j0) < i→n(j) → 0 ≤ j0 → maxScale(i * 10 ^ j0) = j0 ∨ i % 10 = 0 ⊦ i % 10 = 0, maxScale(i * 10 ^ j -1 * 10) = j

Rule argument

spec: int-pot inst: name: Pot-pos seq: ⊦ 0 < i → j ^ i = j ^ i -1 * j subst: [i, j] → [j, 10] flags: rewrite

Additional information

Used terms: j, 10