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Proof step 4 from proof maxScale-pot10-nls (previous step)

0 ≤ j, maxScale(i * 10 ^ j) < j, ∀ j0, i. i→n(j0) < i→n(j) → maxScale(i * 10 ^ j0) < j0 ∧ 0 ≤ j0 → i = 0 ⊦ i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ 0 < i → j ^ i = j ^ i -1 * j
Proof step 6:
0 < j, 0 ≤ j, maxScale(i * 10 ^ j -1 * 10) < j, ∀ j0, i. i→n(j0) < i→n(j) → maxScale(i * 10 ^ j0) < j0 ∧ 0 ≤ j0 → i = 0 ⊦ i = 0

Rule argument

spec: int-pot inst: name: Pot-pos seq: ⊦ 0 < i → j ^ i = j ^ i -1 * j subst: [i, j] → [j, 10] flags: rewrite

Additional information

Used simplifier rules: maxScale-not-negt: ⊦ ¬ maxScale(i) < 0;%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%anti: ⊦ i ≤ j → (j ≤ i ↔ i = j); from specification int-abs%one: ⊦ 1 * i = i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used terms: j, 10