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Proof step 5 from proof mkDecimal-maxScale-le-int (previous step)

¬(i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0), maxScale(i) ≤ abs(j), ∀ i0, j. i→n(i0) < i→n(i) → maxScale(i0) ≤ abs(j) → mkDecimal(i0, j).int = i0 / 10 ^ maxScale(i0) ⊦ mkDecimal(i, j).int = i / 10 ^ maxScale(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
maxScale(i) ≤ abs(j), ∀ i0, j. i→n(i0) < i→n(i) → maxScale(i0) ≤ abs(j) → mkDecimal(i0, j).int = i0 / 10 ^ maxScale(i0) ⊦ mkDecimal(i, j).int = i / 10 ^ maxScale(i), i = 0, j ≠ 0 ∧ i % 10 = 0

Rule argument

Additional information

Used simplifier rules: intvalue-zero: ⊦ mkDecimal(0, j).int = 0;%maxScale-zero: ⊦ maxScale(0) = 0;