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Proof step 5 from proof mkDecimal-maxScale-le-scale (previous step)

¬ ¬(i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0), maxScale(i) ≤ abs(j), ∀ i0, j. i→n(i0) < i→n(i) → maxScale(i0) ≤ abs(j) → abs(j) = mkDecimal(i0, j).scale + maxScale(i0) ⊦ abs(j) = mkDecimal(i, j).scale + maxScale(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
i % 10 = 0, maxScale(i) ≤ abs(j), ∀ i0, j. i→n(i0) < i→n(i) → maxScale(i0) ≤ abs(j) → abs(j) = mkDecimal(i0, j).scale + maxScale(i0) ⊦ j = 0, i = 0, abs(j) = mkDecimal(i, j).scale + maxScale(i)

Proof step 5 from proof mkDecimal-maxScale-le-scale (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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