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Proof step 11 from proof mkDecimal-maxScale-nle-scale (previous step)

i % 10 = 0 ∧ i ≠ 0, i % 10 = 0, abs(j) < maxScale(i / 10) + 1, ∀ i0, j. i→n(i0) < i→n(i) → abs(j) < maxScale(i0) → mkDecimal(i0, j).scale = 0 ⊦ j = 0, i = 0, mkDecimal(i / 10, abs(j) - 1).scale = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
i % 10 = 0, abs(j) ≤ maxScale(i / 10), ∀ i0, j. i→n(i0) < i→n(i) → abs(j) < maxScale(i0) → mkDecimal(i0, j).scale = 0 ⊦ j = 0, mkDecimal(i / 10, abs(j) - 1).scale = 0, i = 0

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%succ-02: ⊦ i < j + 1 ↔ i ≤ j; from specification int-abs