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Proof step 14 from proof mkDecimal-reduce-int (previous step)

mkDecimal(i / 10, abs(j) - 1).int = (i / 10) / 10 ^ min(maxScale(i / 10), abs(abs(j) - 1)), i % 10 = 0, ∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(i0, j).int = i0 / 10 ^ min(maxScale(i0), abs(j)) ⊦ i = 0, mkDecimal(i / 10, abs(j) - 1).int = i / 10 ^ min(maxScale(i / 10) + 1, abs(j)), j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
i % 10 = 0, mkDecimal(i / 10, abs(j) - 1).int = (i / 10) / 10 ^ min(maxScale(i / 10), abs(j) - 1), ∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(i0, j).int = i0 / 10 ^ min(maxScale(i0), abs(j)) ⊦ i = 0, mkDecimal(i / 10, abs(j) - 1).int = i / 10 ^ min(maxScale(i / 10) + 1, abs(j)), j = 0

Rule argument

Additional information

Used simplifier rules: abs-abs: ⊦ j ≠ 0 → abs(abs(j) - 1) = abs(j) - 1; from specification int-abs